-x^2+180x-5600=0

Solution for -x^2+180x-5600=0 equation:

-x^2+180x-5600=0

We add all the numbers together, and all the variables

-1x^2+180x-5600=0

a = -1; b = 180; c = -5600;
Δ = b2-4ac
Δ = 1802-4·(-1)·(-5600)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-100}{2*-1}=\frac{-280}{-2}
=+140
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+100}{2*-1}=\frac{-80}{-2}
=+40
$